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Beeping a Maximal Independent Set

机译:蜂鸣最大独立集

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摘要

We consider the problem of computing a maximal independent set (MIS) in anextremely harsh broadcast model that relies only on carrier sensing. The modelconsists of an anonymous broadcast network in which nodes have no knowledgeabout the topology of the network or even an upper bound on its size.Furthermore, it is assumed that an adversary chooses at which time slot eachnode wakes up. At each time slot a node can either beep, that is, emit asignal, or be silent. At a particular time slot, beeping nodes receive nofeedback, while silent nodes can only differentiate between none of itsneighbors beeping, or at least one of its neighbors beeping. We start by proving a lower bound that shows that in this model, it is notpossible to locally converge to an MIS in sub-polynomial time. We then studyfour different relaxations of the model which allow us to circumvent the lowerbound and find an MIS in polylogarithmic time. First, we show that if apolynomial upper bound on the network size is known, it is possible to find anMIS in O(log^3 n) time. Second, if we assume sleeping nodes are awoken byneighboring beeps, then we can also find an MIS in O(log^3 n) time. Third, ifin addition to this wakeup assumption we allow sender-side collision detection,that is, beeping nodes can distinguish whether at least one neighboring node isbeeping concurrently or not, we can find an MIS in O(log^2 n) time. Finally, ifinstead we endow nodes with synchronous clocks, it is also possible to find anMIS in O(log^2 n) time.
机译:我们考虑在仅依赖载波侦听的极端恶劣的广播模型中计算最大独立集(MIS)的问题。该模型由一个匿名广播网络组成,其中节点不了解网络的拓扑结构,甚至不知道其大小的上限。此外,假设对手选择了每个节点在哪个时隙唤醒。在每个时隙,节点可以发出哔声,即发出信号,也可以保持沉默。在特定的时隙,蜂鸣节点不接收任何反馈,而静默节点只能区分它的邻居没有蜂鸣,或者至少有一个邻居蜂鸣。我们首先证明一个下界,表明在该模型中,不可能在次多项式时间内局部收敛到MIS。然后,我们研究了模型的四个不同松弛,这些松弛使我们能够规避下界并在多对数时间中找到MIS。首先,我们证明如果知道网络大小的多项式上限,则有可能在O(log ^ 3 n)的时间内找到anMIS。其次,如果我们假设睡眠节点被相邻的哔哔声唤醒,那么我们也可以在O(log ^ 3 n)时间中找到一个MIS。第三,如果除此唤醒假设外,我们还允许发送方冲突检测,即蜂鸣节点可以区分至少一个相邻节点是否同时在蜂鸣,我们可以在O(log ^ 2 n)时间内找到一个MIS。最后,如果相反,我们赋予节点同步时钟,则还可以在O(log ^ 2 n)的时间内找到一个MIS。

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